fungsi f dinyatakan dengan f(x) = 10 - 3x - x². tentukan nilai f(x) berikut. a. f(6) b. f(-5) c. f(a) d. f(a+1)

F(x)= 10 - 3x - x²
A.F(6)= 10-3(6)-6²
= 10-18-36
= -8-36
= -42
B.F(-5) =10 - 3(-5) - (-5)²
=10--15-25
=25-25
=0

f(6) = 10-3(6)-(6)x(6)
= -44
f(-5)=10-3(-5)-(-5)x(-5)
=0
f(a)=10-3a-(a)x(a)
f(a+1)=10-3(a+1)-(a+1)x(a+1)
=10-3a-3-(a)x(a)+2a+1
=8-a-(a)x(a)