Matematika

Pertanyaan

hitunglah persamaan aljabar berikut ini!
hitunglah persamaan aljabar berikut ini!

2 Jawaban

  • 1. (3b +5) +(4b -9)
    = 3b + 5 +4b -9
    = 3b +4b +5 -9
    = 7b -4

    2. (-5y -2) -(3y -8)
    = -5y -2 -3y + 8
    = -5y -3y -2 +8
    = -8y +6

    3. 2 (-10m +5)
    = -20m + 10

    4. -5 (8c -4)
    = -40c + 20

    5. 3 (2a +5) +6 (3a -2)
    = 6a +15 +18a -12
    = 6a +18a +15 -12
    = 24a +3
  • 1. (3b+5)+(4b-9) = 3b+4b+5-9 = 7b-4
    2. (-5y-2)-(3y-8) = -5y-2-3y+8 = -5y-3y-2+8 = -8y+6
    3. 2(-10m+5) = (2×-10m)+(2×5) = -20m+10
    4. -5(8c-4) = (-5×8c)+(-5×-4) = -40c+20
    5. 3(2a+5)+6(3a-2) = (3×2a)+(3×5)+(6×3a)+(6×-2)
                                      = 6a+15+18a+(-12)
                                      = 6a+18a+15-12
                                      = 24a+3