hitunglah persamaan aljabar berikut ini!
Matematika
Shanda111
Pertanyaan
hitunglah persamaan aljabar berikut ini!
2 Jawaban
-
1. Jawaban Lianty164
1. (3b +5) +(4b -9)
= 3b + 5 +4b -9
= 3b +4b +5 -9
= 7b -4
2. (-5y -2) -(3y -8)
= -5y -2 -3y + 8
= -5y -3y -2 +8
= -8y +6
3. 2 (-10m +5)
= -20m + 10
4. -5 (8c -4)
= -40c + 20
5. 3 (2a +5) +6 (3a -2)
= 6a +15 +18a -12
= 6a +18a +15 -12
= 24a +3 -
2. Jawaban irayogaswara
1. (3b+5)+(4b-9) = 3b+4b+5-9 = 7b-4
2. (-5y-2)-(3y-8) = -5y-2-3y+8 = -5y-3y-2+8 = -8y+6
3. 2(-10m+5) = (2×-10m)+(2×5) = -20m+10
4. -5(8c-4) = (-5×8c)+(-5×-4) = -40c+20
5. 3(2a+5)+6(3a-2) = (3×2a)+(3×5)+(6×3a)+(6×-2)
= 6a+15+18a+(-12)
= 6a+18a+15-12
= 24a+3