tentukan y=sin2(cos2(1-x))

jawab

p = 1- x
dp/dx = 1

q = cos 2p
dq/dp  = - 2 sin 2p

r = sin 2q
dr/dq =  2 cos 2q

y = r
dy/dr = 1

dy/dx = dy/dr . dr/dq. dq/dp. dp/dx
dy/dx = (1) .(2 cos 2q).(-2 sin 2p).1
dy/dx = - 4 cos 2q sin 2p
dy/dx =  -4 cos 2(cos 2p) sin 2(1-x)
dy/dx = - 4 cos 2 (cos 2(1-x). sin 2(1-x)
dy/dx = - 4 cos 2 (1/2)(2 sin 2(1-x). cos 2(1-x))
dy/dx = - 2 cos 2 ( sin 4(1-x))
dy/dx = - 2 cos 2 (sin( 4 -4x))