1. Tentukan persamaan garis melalui titik H(3,6) dan sejajar garis AB jika A(-1,4) dan B(2,-5) Tolong di jawab besok di kumpul pliss

H (3,6) ==> x1 = 3 ; y1 = 6
:) persamaan garis AB
( y -ya)/(yb-ya) = (x-xa)/(xb-xa)
(y -4)/(-5-4) = ( x - -1)/(2- -1)
(y -4)/-9 = (x +1)/3
y-4= -9(x+1)/3
y-4 = -3(x+1)
y-4 = -3x -1
y= -3x-1+4
y = -3x+3
gradien m ==> y = mx + c
jd m = -3
::) sejajar maka m1 = m2
m2 = -3
pers. garisnya
y - y1 = m(x - x1)
y -6 = -3(x -3)
y -6= -3x+9
y+3x =9+6
3x +y = 15
3x +y-15 =0