(2x-5)^x^2+1 = (2x-5)^x+7

EksPonenSiaL

(2x - 5)^(x² + 1) = (2x - 5)^(x + 7)

•
x² + 1 = x + 7
x² - x - 6 = 0
(x - 3)(x + 2) = 0
x = 3 atau x = -2

••
2x - 5 = 1
2x = 5 + 1
x = 3

Nilai x yg memenuhi :
x = -2 dan x = 3