di ketahui fungsi h(x)=1/2 x + n. jika h(n+ 1)= h(2n - 2),nilai n =
Matematika
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Pertanyaan
di ketahui fungsi h(x)=1/2 x + n. jika h(n+ 1)= h(2n - 2),nilai n =
2 Jawaban
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1. Jawaban Eli3173
h(x) = 1/2 x + n
h(n + 1) = 1/2(n + 1) + n
= 1/2 n + 1/2 + n
= 3/2n + 1/2
h(2n - 2) = 1/2(2n - 2) + n
= n - 1 + n
= 2n - 1
h(n + 1) = h(2n - 2)
3/2 n + 1/2 = 2n - 1
--------------------------- kedua ruas dikali 2
3n + 1 = 4n - 2
4n - 3n = 2 + 1
n = 3 -
2. Jawaban lintangannisa21
h(x) = ½x+n
h(n+1) = h(2n-2)
1/2(n+1)+n = 1/2(2n-2) +n
½n+½+n = n-1+n
1 ½n+ ½ = 2n-1
1 ½n - 2n = -1-½
-½n = -1 ½
n = -1 ½/-½
n = 3