Matematika

Pertanyaan

nomer 2 dan 3 ada yang tau caranya gak??
nomer 2 dan 3 ada yang tau caranya gak??

1 Jawaban

  • 2.A.y-y1 = m(x-x1) 
      y-9 =  (x-5) 
      5(y-9) = 3(x-5) 
      5y-45 = 3x-15 
      -3x + 5y -30 = 0 

      B.y-y1 = m(x-x1)
      y-3 =  (x-6)
      2(y-3) = -1 (x-6)
      2y-6 = -x+6
      x+2y-12=0

    3.RUMUS: y-y1 : y2-y1 = x-x1 : x2
    A.y-6 : -4-6 = x-2 : -1-2
    y-6 : -10 = x-2 : -3 (kemudian kalikan silang)
    -3(y-6) = -10(x-2)
    -3y+18 = -10x+20 
    -3y+10y =20-18
    -3y+10x =2
    B.y-3:-5-3 + x-1 : 8-1
    y-3 : -8 = x-1 : 7
    7(y - 3) = -8(x-1)
    7y - 21= -8x + 8
    7y+8x = 8+21
    7y+8x=29

    semoga bermanfaat :>