nomer 2 dan 3 ada yang tau caranya gak??
Matematika
Jeanie11
Pertanyaan
nomer 2 dan 3 ada yang tau caranya gak??
1 Jawaban
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1. Jawaban firazantifirdaus
2.A.y-y1 = m(x-x1)
y-9 = (x-5)
5(y-9) = 3(x-5)
5y-45 = 3x-15
-3x + 5y -30 = 0
B.y-y1 = m(x-x1)
y-3 = (x-6)
2(y-3) = -1 (x-6)
2y-6 = -x+6
x+2y-12=0
3.RUMUS: y-y1 : y2-y1 = x-x1 : x2
A.y-6 : -4-6 = x-2 : -1-2
y-6 : -10 = x-2 : -3 (kemudian kalikan silang)
-3(y-6) = -10(x-2)
-3y+18 = -10x+20
-3y+10y =20-18
-3y+10x =2
B.y-3:-5-3 + x-1 : 8-1
y-3 : -8 = x-1 : 7
7(y - 3) = -8(x-1)
7y - 21= -8x + 8
7y+8x = 8+21
7y+8x=29
semoga bermanfaat :>