Fisika

Pertanyaan

fisika kelas 9
rumus rumus fisika

1 Jawaban

  • Rumus:

    {\displaystyle \!L_{t}=\!L_{0}(\!1+\alpha \times \Delta t)}

    {\displaystyle \!L_{t}} = panjang akhir (m, cm){\displaystyle \!L_{0}} = panjang awal (m, cm){\displaystyle \alpha } = koefisien muai panjang (/°C){\displaystyle \Delta t} = perbedaan suhu (°C)

    Muai volume

    Rumus:

    {\displaystyle \!V_{t}=\!V_{0}(\!1+\gamma \times \Delta \!t)}

    Keterangan:

    {\displaystyle \!V_{t}} = volume akhir (m3, cm3){\displaystyle \!V_{0}} = volume awal (m3, cm3){\displaystyle \gamma } = {\displaystyle \!3\alpha } = koefisien muai volume (/°C){\displaystyle \Delta t} = selisih suhu (°C)

    Muai luas

    Rumus:

    {\displaystyle \!A_{t}=\!A_{0}(\!1+\beta \times \Delta t)}

    Keterangan:

    {\displaystyle \!A_{t}} = luas akhir (m2, cm2){\displaystyle \!A_{0}} = luas awal (m2, cm2){\displaystyle \beta } = {\displaystyle \!2\alpha } = koefisien muai luas (/°C){\displaystyle \Delta t} = selisih suhu (°C)


    #Smoga mmbantu

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