sejajar garis y=3/2x-5 dan melalui titik (-2,1)

y = 3/2x - 5, berikut gradien m = 3/2 dan melalui (-2,1)
y - y1 = m(x - x1)
y - 1 = 3/2(x - -2)
y - 1 = 3/2(x + 2)
y - 1 = 3/2x + 3
y = 3/2x +3 +1
y = 3/2x + 4 atau 3x - 2y +8 = 0