nilai dari²log 4 + ²log 12 -²log 6 =

2 log 4 + 2 log 12 - 2 log 6
=2 log (4*12/6)
=2 log 8
= 3

semoga membantu

Berdasarkan
[tex]\log_nab=\log_na+\log_nb \\ \log_n \frac{a}{b}=\log_na-\log_nb[/tex]
Diperoleh
[tex]=\log_24 + \log_212 - \log_26 =\\ = \log_2(4 \times 12 : 6) \\ = \log_2 8 \\ =3[/tex]
Maka
[tex]\therefore \log_24+\log_212- \log_26 = 3[/tex]