tolong bantu soal ini yaaa, beserta cara, makasihhhh

LogAritMa

⁴log 3 = a
²log 3 = 2a

2'log √3 + 3 . 8'log 9
= 2'log 3^1/2 + 3 . (2³)'log 3²
= 1/2 . ²log 3 + 3 .2/3 . ²log 3
= (1/2 + 2) . ²log 3
= 5/2 . 2a
= 5a ✔

^2log√3 + 3 ^8log9
= ^2log√3 + 3 ^2^3log9
= ^2log(3)^1/2 + ^2log3^2
= ^2log [(3)^1/2 x 3^2]
= ^2log 3^5/2
= 5/2 ^2log3
= 5 ^2^2log3
= 5 ^4log3
= 5a Jawaban D

Semoga membantu, Tetap semangat
JKira