volume benda putar yang dibatasi y=x+2, garis x=0 x=3 dan diputar 360°

jawab

y = x + 2
batas integral x = 0 sd  x = 3

Volume = π ₀³∫ y² dx
V = π ₀³∫ (x+2)² dx
V = π ₀³ ∫ x² + 4x + 4 dx
V = π [ 1/3 x³ + 2x² + 4x]³₀
V = π [ 1/3 (27) + 2(9) + 4(3)]
V = π ( 9+18 + 12)
V = 39 π