Matematika

Pertanyaan

sederhanakan 8^log 32 + 4 8^log 4 - 8^log 128

2 Jawaban

  • ⁸log32 + 4. ⁸log4 - ⁸log128
    = ⁸log32 + ⁸log4⁴ - ⁸log128
    = ⁸log32 + ⁸log256 - ⁸log128
    = ⁸log(32 x 256 : 128)
    = ⁸log(32 x 2)
    = ⁸log64
    = ⁸log8²
    = 2 . ⁸log8
    = 2
  • Materi : Logaritma
    Kelas : X SMA

    ⁸log 32  + 4 . ⁸log 4 - ⁸log128
    = 5/3 ²log2 + 4 . 2/3 ²log2 - 7/3 ²log2
    = 5/3 + 8/3 - 7/3 . 1
    = 6/3
    = 2

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