Jika A dan B di kwadran 1 sin A=3/5 sin B=5/13tentukan a. Sin (A+b) b. Tan (A+b)

sin A = 3/5, maka cos A = 4/5 dan tan A = 3/4

sin B = 5/13, maka cos B = 12/13 dan tan B = 5/12

sin (A + B) = sin A cos B + cos A sin B
= 3/5 . 12/13 + 4/5 . 5/13
= (36 + 20)/65
= 56/65

tan (A + B) = (tan A + tan B) ÷ (1 - tan A . tan B)
= (3/4 + 5/12) ÷ (1 - (3/4 . 5/12))
= 14/12 ÷ (1 - (5/16))
= 7/6 ÷ 11/16
= 7/6 × 16/11
= 56/33