bantu jawab................
Matematika
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Pertanyaan
bantu jawab................
1 Jawaban
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1. Jawaban ahreumlim
f(x) = x² - 1
f(-3) = (-3)² - 1 = 9 - 1 = 8
f(-1) = (-1)² - 1 = 1 - 1 = 0
f(0) = (0)² - 1 = 0 - 1 = -1
f(2) = (2)² - 1 = 4 - 1 = 3
f(3) = (3)² - 1 = 9 - 1 = 8
(* karena f(a) = f(-a) maka range fungsinya di mulai dari f(0) sampai f(3)
Rf = {f(0) ≤ y ≤ f(3) , y ∈ R}
= {-1 ≤ y ≤ 8 , y ∈ R}
f(a) = a² - 1
a² - 1 = 3
a² = 4
a = -2 atau a = 2