tolong dijawab soal difoto ini

x+2y+3z =8
x = 8-2y-3z

3x-2y+z =16
3(8-2y-3z)-2y+z = 16
24-6y-9z-2y+z =16
-8y-8z = -8     ( sama-sama dibagi -8)
y+z =1
y=1-z ..........(1)

x= 8-2y-3z substitusi ke 2x+3y-z=3
2(8-2y-3z)+3y-z =3
16-4y-6z+3y-z=3
-y-7z = 13............(2)

y=1-z substitusi ke -y-7z=13
-1+z-7z=13
-6z = 14
z= 14/6
z= 7/3

y=1-z
y=1-7/3
y= -1/3

x=8-2y-3z
x= 8- 2(-1/3)-3(7/3)
x= 8+2/3-7
x= 1+2/3
x= 5/3

jadi (x,y,z)= (5/3, -1/3, 7/3)