nilai p yang memenuhi p'log 6 - p'log 9 + p'log 1/2 = -1 adalah

Bab Logaritma
Matematika SMA Kelas X

^ = pangkat

^plog 6 - ^plog 9 + p^log (1/2) = -1
^plog ((6 . 1/2) : 9) = -1
6/18 = p⁻¹
1/3 = 1/p
p = 3

p'log 6 - p'log 9 + p'log 1/2 = -1
p'log (6/9)(1/2) = -1 p'log p
p'log (1/3) = p'log p^-1
1/p = 1/3
p = 3

Semoga membantu, Tetap semangat
JKira