diketahui 2log 3 = x dan 2log 10 = y. nilai 6log 120 =

2log3 = x;
2log10 = y;

[tex]6log120 = \frac{log120}{log6} = \frac{log10 + log3 + log2 + log2}{log3 + log2} [/tex]

sesuai aturan logaritma, maka bisa dijadikan 2log

[tex]\frac{2log10 + 2log3 + 2log2 + 2log2}{2log3 + 2log2} = \frac{y+x+1+1}{x+1} = \frac{y+x+2}{x+1}[/tex]