Matematika

Pertanyaan

nilai 2'log'2 6 - 2'log'2 3 ÷ 2'log 18 = ?

2 Jawaban

  • 6-3:2log 18
    3:2log2.9
    3:9
    2
  • ²log²6 - ²log²3 : ²log18
    = (²log6)² - (²log3)² : ²log 18
    = (²log6 + ²log3)(²log6 - ²log3) : ²log18
    = (²log(6x3))(²log6/3)) : ²log18
    = (²log18 . ²log2) : ²log18
    = (²log18 . 1) : ²log18
    = ²log18 : ²log18
    = 1

Pertanyaan Lainnya