√12+√75-√3-√147 mohon beserta rumusnya

[tex] \sqrt{12} = 2 \sqrt{3} \\ \sqrt{75} = 5 \sqrt{3} \\ \sqrt{3} = \sqrt{3} \\ \sqrt{147} = 7 \sqrt{3} \\ 2 \sqrt{3} + 5 \sqrt{3 } - \sqrt{3} - 7\sqrt{3} = (2 + 5 - 1 - 7) \sqrt{3} = - 1 \sqrt{3} = - \sqrt{3} [/tex]
Semoga bermanfaat :)