Matematika

Pertanyaan

1/3 log125 - 2 log4 + log32=

1 Jawaban

  • LogAritMa

    1/3 log 125 - 2 log 4 + log 32
    = log 125^1/3 - log 4² + log 32
    = log (5/4² × 32)
    = log 10
    = 1 ✔

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