luas selimut sebuah kerucut 550 cm2, jari jarinya 7 cm. berapa volumenya?? tolong dijelasin....

luas selimut=π×r×s
550=22/7×7×s
550=154/7×s
550=22s
s=550/22
s=25



t=√s²-r²
=√25²×7²
=√625-49
=√576
=24


volume kerucut =1/3×π×r²×t
=1/3×22/7×7×7×24
=1/3×25872/7
=1/3×3696
=3696/3
=1232 cm³