Diketahui cos(A-B)=3/5, cos AcosB=7/2, tan A tan B
Matematika
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Pertanyaan
Diketahui cos(A-B)=3/5, cos AcosB=7/2, tan A tan B
1 Jawaban
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1. Jawaban Anonyme
TriGonoMetRi
cos (A - B) = 3/5
cos A cos B + sin A sin B = 3/5
7/2 + sin A sin B = 3/5
sin A sin B = 3/5 - 7/2
sin A sin B = (6 - 35)/10
sin A sin B = -29/10
tan A tan B
= sin A sin B / cos A cos B
= (-29/10) / (7/2)
= -29/10 × 2/7
= -29/35 ✔