-5(2y²-3y+8) dari 3(7y²+6y-5)
Matematika
seger3
Pertanyaan
-5(2y²-3y+8) dari 3(7y²+6y-5)
1 Jawaban
-
1. Jawaban Tehirooo
-5(2y-3y+8) = -10y^2+15y-40
3(7y^2-6y-5)= 21y^2-18y-15
= -10y^2+15y-40+21y^2-18y-15
=( 21y^2-18y-15)-( -10y^2+15y-40)
=21y^2-18y-15+10y^2+15y-40
=21y^2+10y^2-18y+15y-15-40
=31y^2-3y-55