Hasil dari sin 30 + cos 60 - 2 tan 45

[tex]\sin 30^{\circ}=\frac{1}{2}[/tex]
[tex]\cos 60^{\circ}=\frac{1}{2}[/tex]
[tex]\tan 45^{\circ}=\frac{\sin 45^{\circ}}{\cos 45^{\circ}} \\ \tan 45^{\circ}=\frac{\frac{1}{2}\sqrt2}{\frac{1}{2}\sqrt2} \\ \therefore \tan 45^{\circ}=1[/tex]
Sehingga kita peroleh
[tex] \sin 45^{\circ} + \cos 60^{\circ} - 2\tan 45^{\circ}=\frac{1}{2}+\frac{1}{2}-2(1) \\ \sin 45^{\circ}+\cos 60^{\circ}-2\tan 45^{\circ} = 1 - 2 \\ \therefore \sin 45^{\circ} + \cos 60^{\circ} - 2\tan 45^{\circ}=-1[/tex]