Matematika

Pertanyaan

1.tentukan himpunan penyelesaian persamaan berikut. A. 1 per 2 [a-6] = 5 B. x - 1 per 2 = 6 + 1 per 2 x C. [p - 3] = 2 per 3 [p + 4] D. 2 y - 11 per 3 = 5 y + 5 per 5

1 Jawaban

  • A.) 1/2 [a-6]
    ≈ 1/2a-1/2×6
    ≈ 1/2a-3

    B.) x-1/2 = 6+1/2
    ≈ x-1/2 = 7/2
    ≈ x-1 = 7
    ≈ x=7+1
    ≈ x=8

    C.)[p-3] = 2/3[p+4]
    ≈ p-3 = 2/3p + 8/3
    ≈ 3p-9 = 2p+8
    ≈ 3p-9 = 8+9
    ≈ p=17

    D.)2y-11/3 = 5y+5/5
    ≈ 2y-11/3 = 5(y+1)/5
    ≈ 2y-11/3 = y+1
    ≈2y-11 = 3y+3
    ≈2y-3y = 3 +11
    ≈ -y=14
    ≈ y=-14

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