Rangkaian gabungan R1=2ohm R2=2ohm R3=2 ohm R4=2ohm voltnya 6 ditanya hitunglah jumlah kuat arus listrik nya?

jika disusun scr seri
R total= R1 +R2+R3+R4
= 2+2+2+2
= 8 ohm

jika disusun PARALEL
1/Rp = 1/r1 +1/r2 + 1/r3 + 1/r4
1/Rp = 1/2+1/2+ 1/2+ 1/2
1/Rp = 4/2
Rp = 2/4
Rp = 0,5 ohm

(seri)
V = I.R
I = 6/ 8 = 3/4 = 0,75 ampere

(paralel)
I = 6/0,5 = 12 ampere

tapi sepertinya yg benar scr PARALEL .